The number of octahedral and tetrahedral holes respectively present in a hexagonal close packed (hcp) crystal of ' X ' atoms are

Question

The number of octahedral and tetrahedral holes respectively present in a hexagonal close packed (hcp) crystal of ' X ' atoms are (A) X, 2 X (B) X, X (C) 2X, X (D) 2 X, 2 X

Tardigrade Admin · Accepted Answer

In a close packed structure (h c p or c c p) (i) Number of octahedral voids = Number of particles present in the close packing (ii) Number of tetrahedral voids =2 × Number of octahedral voids.

Q. The number of octahedral and tetrahedral holes respectively present in a hexagonal close packed (hcp) crystal of ' $X$ ' atoms are

X, 2 X

X, X

2X, X

2 X, 2 X

In a close packed structure $(h c p$ or $cc p)$

(i) Number of octahedral voids $=$ Number of particles present in the close packing

(ii) Number of tetrahedral voids $= 2 \times$ Number of octahedral voids.

Q. The number of octahedral and tetrahedral holes respectively present in a hexagonal close packed (hcp) crystal of ' X ' atoms are