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Q. The number of octahedral and tetrahedral holes respectively present in a hexagonal close packed (hcp) crystal of ' $X$ ' atoms are

EAMCETEAMCET 2013

Solution:

In a close packed structure $(h c p$ or $c c p)$

(i) Number of octahedral voids $=$ Number of particles present in the close packing

(ii) Number of tetrahedral voids $=2 \times$ Number of octahedral voids.