Question

The number of moles of oxalate ions oxidized by one mole of $Mn{O}_4^{-}$ ion is

• A. $1/5$
• B. $2/5$
• C. $5/2$
• D. $5$

Answer 1

Answer: (C)

The balanced equation is
$5C_2{O}_4^{2-}+26H^{+}+2Mn{O}_4^{-}\to +5C{O}_2+18H_{2}O+2M{n}^{2+}$
Now 2 moles of $Mn{O}_4^{-}$ requires $C_2{O}_4^{-2}=5$ mol
$\therefore$ 1 mol of $Mn{O}_4^{-}\to \frac{5}{2}mol$