The number of mole of MnO 4- required by 1 mole of ferric oxalate for oxidation is/are-

Question

The number of mole of MnO 4- required by 1 mole of ferric oxalate for oxidation is/are- (A) 0.2 (B) 1.2 (C) 2.6 (D) 5.2

Tardigrade Admin · Accepted Answer

48 H ++6 MnO 4-+5 Fe 2( C 2 O 4)3 arrow 6 Mn 2++3 CO 2+ 10 Fe 3++24 H 2 O 5 moles of ferric oxalate require MnO 4-=6 moles 1 moles of ferric oxalate require MnO 4-=(6/5)=1.2

Q. The number of mole of $M n O_{4}^{-}$ required by 1 mole of ferric oxalate for oxidation is/are-

0.2

1.2

2.6

5.2

$48 H^{+} + 6 M n O_{4}^{-} + 5 F e_{2} (C_{2} O_{4})_{3} \to 6 M n^{2 +} + 3 C O_{2} +$

$10 F e^{3 +} + 24 H_{2} O$

5 moles of ferric oxalate require $M n O_{4}^{-} = 6$ moles

1 moles of ferric oxalate require $M n O_{4}^{-} = \frac{6}{5} = 1.2$

Q. The number of mole of MnO4−​ required by 1 mole of ferric oxalate for oxidation is/are-

0.2

1.2

2.6

5.2

48H++6MnO4−​+5Fe2​(C2​O4​)3​→6Mn2++3CO2​+ 10Fe3++24H2​O 5 moles of ferric oxalate require MnO4−​=6 moles 1 moles of ferric oxalate require MnO4−​=56​=1.2

Q. The number of mole of $M n O_{4}^{-}$ required by 1 mole of ferric oxalate for oxidation is/are-

$48 H^{+} + 6 M n O_{4}^{-} + 5 F e_{2} (C_{2} O_{4})_{3} \to 6 M n^{2 +} + 3 C O_{2} +$

$10 F e^{3 +} + 24 H_{2} O$

5 moles of ferric oxalate require $M n O_{4}^{-} = 6$ moles

1 moles of ferric oxalate require $M n O_{4}^{-} = \frac{6}{5} = 1.2$