The number of isomers of the aromatic compound C8H10 is:

Question

The number of isomers of the aromatic compound C8H10 is: (A) 3 (B) 4 (C) 2 (D) 5

Tardigrade Admin · Accepted Answer

(i) textD.U= textC+1-(. ( textH/2) .)=8+1-(. (10/2) .) =4 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-1ccn5md05atejz3r.jpg" /> Total number of aromatic isomers = 4.

Q. The number of isomers of the aromatic compound C₈H₁₀is:

3

4

2

5

(i) $D.U = C + 1 - (\frac{H}{2}) = 8 + 1 - (\frac{10}{2})$
$= 4$

Total number of aromatic isomers = 4.

Q. The number of isomers of the aromatic compound C8H10 is:

3

4

2

5

(i) D.U=C+1−(2H​)=8+1−(210​) =4 Total number of aromatic isomers = 4.

Q. The number of isomers of the aromatic compound C₈H₁₀is:

(i) $D.U = C + 1 - (\frac{H}{2}) = 8 + 1 - (\frac{10}{2})$
$= 4$

Total number of aromatic isomers = 4.