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  4. The number of isomers of the aromatic compound C8H10 is:

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Q. The number of isomers of the aromatic compound C8H10 is:

NTA AbhyasNTA Abhyas 2022

Solution:

(i) $\text{D.U}=\text{C}+1-\left(\right. \frac{\text{H}}{2} \left.\right)=8+1-\left(\right. \frac{10}{2} \left.\right)$
$=4$
Solution

Total number of aromatic isomers = 4.