The number of integral values of ' a ' for which the quadratic equation (x+a)(x+2016)+1=0 has integral roots, is equal to

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Tardigrade Admin · Accepted Answer

(x+a)(x+2016)=-1 x+a=1, x+2016=-1 text or x+a=-1, x+2016=1 a=+2018, x=-2017, text or x=-2015 ⇒ a=2014

Q. The number of integral values of ' $a$ ' for which the quadratic equation $(x + a) (x + 2016) + 1 = 0$ has integral roots, is equal to