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Q. The number of integral values of ' $a$ ' for which the quadratic equation $(x+a)(x+2016)+1=0$ has integral roots, is equal to

Complex Numbers and Quadratic Equations

Solution:

$(x+a)(x+2016)=-1 $
$x+a=1, x+2016=-1 \text { or } x+a=-1, x+2016=1$
$a=+2018, x=-2017, \text { or } x=-2015 \Rightarrow a=2014$