Q.
The number of hexagonal faces that are present in a truncated
octahedron is
1431
189
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Answer: 8
Solution:
The truncated octahedron is the 14 -faced Archimedean solid, with 14 total faces : 6 squares and 8 regular hexagons.
The truncated octahedron is formed by removing the six right square pyramids one from each point of a regular octahedron as :