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Q. The number of hexagonal faces that are present in a truncated octahedron is

IIT JEEIIT JEE 2011The Solid State

Solution:

The truncated octahedron is the $14$ -faced Archimedean solid, with $14$ total faces : $6$ squares and $8$ regular hexagons.
The truncated octahedron is formed by removing the six right square pyramids one from each point of a regular octahedron as :

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