11n>10n+9n ⇒11n−9n>10n ⇒(10+1)n−(10−1)n>10n ⇒{nC1⋅10n−1+nC310n−0+nC510n−5+……}>10n ⇒2n⋅10n−1+2{nC310n−3+nC510n−5+…….}>10n .... (1)
For n=5 105+2{5C3102+5C5}>105 (True)
For n=6,7,8,…….100 2n10n−1>10n ⇒2n10n−1+2{nC310n−3+nC510n−5+……..3>10∘ ⇒11n−9n>10n For n=5,6,7,…….100
For n=4, Inequality (1) is not satisfied ⇒ Inequality does not hold good for N=1,2,3,4
So, required number of elements =96