Question

The number of electrons with azimuthal quantum number $l=1$ and $l=2$ for $Cr$ in ground state are respectively

• A. $16,5$
• B. $16,4$
• C. $12,4$
• D. $16,3$
• E. $12,5$

Answer 1

Answer: (E)

Electronic configuration of

${}_{24}Cr=1s^2,2s^2,2p^6,3s^2,3p^6,4s^1,3d^5$

Given, azimuthal quantum number $(l)=1\Rightarrow p$ -orbital azimuthal quantum number $(l)=2$

$\Rightarrow d$ -orbital. So, number of electrons in $p$ -orbital $=12$ and number of electrons in d-orbital $=5$.