The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of + 2.4 C is

Question

The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of + 2.4 C is (A) 2.5×1019 (B) 1.5×1019 (C) 1.5×10-19 (D) 2.5×10-19

Tardigrade Admin · Accepted Answer

Total charge, q = + 2.4 C Then by quantization of charge, q = ne ∴ number of electrons, n=(q/e)=(2.4 C/1.6×10-19 C)=1.5×1019

Q. The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of $+ 2.4 C$ is

$2.5 \times 1 0^{19}$

$1.5 \times 1 0^{19}$

$1.5 \times 1 0^{- 19}$

$2.5 \times 1 0^{- 19}$

Total charge, $q = + 2.4 C$
Then by quantization of charge, $q = n e$
$∴$ number of electrons, $n = \frac{q}{e} = \frac{2.4 C}{1.6 \times 1 0 ^{- 19} C} = 1.5 \times 1 0^{19}$

Q. The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of +2.4C is

2.5×1019

1.5×1019

1.5×10−19

2.5×10−19