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  4. The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of + 2.4 C is

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Q. The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of $+ 2.4\, C$ is

Electric Charges and Fields

Solution:

Total charge, $q = + 2.4 \,C$
Then by quantization of charge, $q = ne$
$\therefore $ number of electrons, $n=\frac{q}{e}=\frac{2.4\,C}{1.6\times10^{-19}\,C}=1.5\times10^{19}$