The number of electrons supplied at the cathode during electrolysis by a current of 2 ampere in 2 minutes is (charge of electron = 1.6 × 10-19 C)

Question

The number of electrons supplied at the cathode during electrolysis by a current of 2 ampere in 2 minutes is (charge of electron = 1.6 × 10-19 C) (A) 6.02 × 1023 (B) 1.5 × 1020 (C) 0.5 × 1022 (D) 0.6 × 1020

Tardigrade Admin · Accepted Answer

96500 C arrow NA number of electron (2× 60 × 2)C arrow (NA× 240/96500) = 0.015 × 1023 = 0.15 × 1022

Q. The number of electrons supplied at the cathode during electrolysis by a current of 2 ampere in 2 minutes is (charge of electron = $1.6 \times 1 0^{- 19}$ C)

$6.02 \times 1 0^{23}$

$1.5 \times 1 0^{20}$

$0.5 \times 1 0^{22}$

$0.6 \times 1 0^{20}$

96500 C $\to$ NA number of electron
$(2 \times 60 \times 2) C \to \frac{N _{A} \times 240}{96500} = 0.015 \times 1 0^{23}$
= $0.15 \times 1 0^{22}$

Q. The number of electrons supplied at the cathode during electrolysis by a current of 2 ampere in 2 minutes is (charge of electron = 1.6×10−19 C)

6.02×1023

1.5×1020

0.5×1022

0.6×1020