Question

The number of electrons supplied at the cathode during electrolysis by a current of 2 ampere in 2 minutes is (charge of electron = $1.6 \times 10^{-19}$ C)

• A. $6.02 \times 10^{23}$
• B. $1.5 \times 10^{20}$
• C. $0.5 \times 10^{22}$
• D. $0.6 \times 10^{20}$

Answer 1

Answer: (C)

96500 C $\rightarrow$ NA number of electron
$(2\times 60 \times 2)C \rightarrow \frac{N_A\times 240}{96500} = 0.015 \times 10^{23}$
= $0.15 \times 10^{22}$