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Tardigrade
Question
Chemistry
The number of electrons lost or gained during the change 3Fe+4H2O arrow Fe3O4 + 4H2 is
Q. The number of electrons lost or gained during the change
3
F
e
+
4
H
2
O
→
F
e
3
O
4
+
4
H
2
is
10544
218
Redox Reactions
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A
2
11%
B
4
25%
C
6
16%
D
8
48%
Solution:
F
e
3
O
4
=
F
e
O
+
F
e
2
O
3
Therefore, the change can be represented as
F
e
−
−
−
>
F
e
2
+
+
2
e
−
2
F
e
−
−
−
−
>
2
f
e
3
+
+
6
e
−
Number of electrons transferred = 8.