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Chemistry
The number of electrons lost or gained during the change 3Fe+4H2O arrow Fe3O4 + 4H2 is
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Q. The number of electrons lost or gained during the change $3Fe+4H_2O \rightarrow Fe_3O_4 + 4H_2$ is
Redox Reactions
A
2
11%
B
4
25%
C
6
16%
D
8
48%
Solution:
$Fe_3O_4=FeO+Fe_2O_3$
Therefore, the change can be represented as
$Fe--->Fe^{2+}+2e^-$
$2Fe---->2fe^{3+}+6e^-$
Number of electrons transferred = 8.