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Question
Mathematics
The number of distinct terms in the expansion of (x + y2)13 + (x2 + y)14 is ..
Q. The number of distinct terms in the expansion of
(
x
+
y
2
)
13
+
(
x
2
+
y
)
14
is _______..
1684
186
Binomial Theorem
Report Error
Answer:
28
Solution:
To get common terms in both the expamuen
x
r
1
(
y
2
)
13
−
r
1
=
(
y
)
14
−
r
1
(
x
2
)
r
2
∴
r
1
=
2
r
2
and
26
−
2
r
1
=
14
=
r
2
∴
r
1
=
8
,
r
2
=
4
∴
Only one term ts common