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Q.
The number of distinct terms in the expansion of $(x + y^{2})^{13} + (x^{2} + y)^{14}$ is _______..
Binomial Theorem
Solution:
To get common terms in both the expamuen
$x^{r_{1}} (y^{2})^{13-r_{1}} =(y)^{14-r_{1}} (x^{2})^{r_{2}}$
$\therefore r_{1}= 2r_{2}$ and $26-2r_{1} =14=r_{2}$
$\therefore r_{1} =8, r_{2}=4$
$\therefore $ Only one term ts common