Question

The nth term of the sequence $\frac{1}{2},\frac{1}{6},\frac{1}{12}$ ............. is

• A. $\frac{1}{n^2+n}$
• B. $\frac{1}{n}+\frac{1}{n+1}$
• C. $\frac{1}{n^2+2}$
• D. $\frac{1}{n+3}$

Answer 1

Answer: (A)

Sequence is $\frac{1}{1.2},\frac{1}{2.3},\frac{1}{3.4},.......$
$\therefore n$th term $=\frac{1}{n\left(n+1\right)}=\frac{1}{n^2+n}$