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  4. The nth term of the sequence (1 /2), (1 /6), (1 /12) ............. is

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Q. The nth term of the sequence $\frac {1} {2}, \frac {1} {6}, \frac {1} {12}$ ............. is

Sequences and Series

Solution:

Sequence is $\frac{1}{1.2} , \frac{1}{2.3}, \frac{1}{3.4}, .......$
$\therefore n$th term $= \frac{1}{n\left(n+1\right)} = \frac{1}{n^{2}+n}$