The normality of mixture obtained by mixing 100 mL of 0.2 M H 2 SO 4+100 mL of 0.2 M NaOH is :

Question

The normality of mixture obtained by mixing 100 mL of 0.2 M H 2 SO 4+100 mL of 0.2 M NaOH is : (A) 0.2 (B) 0.01 (C) 0.1 (D) 0.3

Tardigrade Admin · Accepted Answer

Given H2 S O4-V=100 m L N=0.2 M N a O H-V=100 m L N=0.2 M Milliequivalent of H 2 SO 4=100 × 0.2 × 2=40(∴ it is dibasic acid ) Milliequivalent of N a O H=100 × 0.1 × 1=20 ∴ Milliequivalent of H2 S O4 left =40-20=20 Total volume =100 mL +100 mL =200 mL Normality of H2 S O4(l e f t)=(20/200)=0.1 N

Q. The normality of mixture obtained by mixing 100mL of 0.2MH2​SO4​+100mL of 0.2MNaOH is :

0.2

0.01

0.1

0.3

Given H2​SO4​−V=100mLN=0.2M NaOH−V=100mLN=0.2M Milliequivalent of H2​SO4​=100×0.2×2=40(∴ it is dibasic acid ) Milliequivalent of NaOH=100×0.1×1=20 ∴ Milliequivalent of H2​SO4​ left =40−20=20 Total volume =100mL+100mL=200mL Normality of H2​SO4​(left)=20020​=0.1N

Q. The normality of mixture obtained by mixing $100 m L$ of $0.2 M H_{2} S O_{4} + 100 m L$ of $0.2 M N a O H$ is :