Thank you for reporting, we will resolve it shortly
Q.
The normality of mixture obtained by mixing $100\, mL$ of $0.2 \,M H _{2} SO _{4}+100\, mL$ of $0.2\, M\,
NaOH$ is :
Bihar CECEBihar CECE 2004
Solution:
Given
$H_{2} S O_{4}-V=100 \,m L \,\,N=0.2\, M$
$N a O H-V=100\, m L\,\, N=0.2\, M$
Milliequivalent of $H _{2} SO _{4}=100 \times 0.2 \times 2=40(\therefore $ it is dibasic acid $)$
Milliequivalent of $N a O H=100 \times 0.1 \times 1=20$
$\therefore $ Milliequivalent of $H_{2} S O_{4}$ left $=40-20=20$
Total volume $=100 \,mL +100\, mL =200 \,mL$
Normality of $H_{2} S O_{4}(l e f t)=\frac{20}{200}=0.1 \,N$