The normality of a solution containing 31.5 gm. of hydrated oxalic acid ( C 2 H 2 O 4 ⋅ 2 H 2 O ) in 1250 ml. of solution is

Question

The normality of a solution containing 31.5 gm. of hydrated oxalic acid ( C 2 H 2 O 4 ⋅ 2 H 2 O ) in 1250 ml. of solution is (A) 0.1 N (B) 0.2 N (C) 0.4 N (D) 0.6 N

Tardigrade Admin · Accepted Answer

Wt. of oxalic acid =31° .5 gm. Volume of solution =1250 ml. ∵ Equivalents of oxalic acid =(31.5/63)=0.5 ∴ Normality of solution =(0.5/1250) × 1000 =0.4 N

Q. The normality of a solution containing $31.5$ gm. of hydrated oxalic acid $(C_{2} H_{2} O_{4} \cdot 2 H_{2} O)$ in $1250 m l$ . of solution is

0.1 N

0.2 N

0.4 N

0.6 N

Wt. of oxalic acid $= 3 1^{\circ} .5 g m$ .
Volume of solution $= 1250 m l$ .
$∵$ Equivalents of oxalic acid $= \frac{31.5}{63} = 0.5$
$∴$ Normality of solution $= \frac{0.5}{1250} \times 1000$
$= 0.4 N$

Q. The normality of a solution containing 31.5 gm. of hydrated oxalic acid (C2​H2​O4​⋅2H2​O) in 1250ml. of solution is