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Q. The normality of a solution containing $31.5$ gm. of hydrated oxalic acid $\left( C _{2} H _{2} O _{4} \cdot 2 H _{2} O \right)$ in $1250 ml$. of solution is

Rajasthan PMTRajasthan PMT 2003

Solution:

Wt. of oxalic acid $=31^{\circ} .5 \,gm$.
Volume of solution $=1250 \,ml$.
$\because$ Equivalents of oxalic acid $=\frac{31.5}{63}=0.5$
$\therefore $ Normality of solution $=\frac{0.5}{1250} \times 1000$
$=0.4 \, N $