The motion of a particle executing SHM in one dimension is described by x=-0.5 sin (2t+π /4), where x is in metre and t in second. The frequency of oscillation in Hz is

Question

The motion of a particle executing SHM in one dimension is described by x=-0.5 sin (2t+π /4), where x is in metre and t in second. The frequency of oscillation in Hz is (A)  2  (B)  π  (C)  π /2  (D)  1/π

Tardigrade Admin · Accepted Answer

Given, equation of SHM x=-0.5 sin (2 t+π / 4) Now, comparing with general equation of SHM, we get x=A sin (ω t+φ) we get ω=2 or 2 π f=2 or f=(1/π) H z

Q. The motion of a particle executing SHM in one dimension is described by $x = - 0.5 sin (2 t + π /4),$ where $x$ is in metre and $t$ in second. The frequency of oscillation in $Hz$ is

$2$

$π$

$π /2$

$1/ π$

Given, equation of SHM $x = - 0.5 sin (2 t + π /4)$
Now, comparing with general equation of SHM,
we get $x = A sin (ω t + ϕ)$
we get $ω = 2$ or $2 π f = 2$
or $f = \frac{1}{π} Hz$

Q. The motion of a particle executing SHM in one dimension is described by x=−0.5sin(2t+π/4), where x is in metre and t in second. The frequency of oscillation in Hz is

2

π

π/2

1/π

Given, equation of SHM x=−0.5sin(2t+π/4) Now, comparing with general equation of SHM, we get x=Asin(ωt+ϕ) we get ω=2 or 2πf=2 or f=π1​Hz

Q. The motion of a particle executing SHM in one dimension is described by $x = - 0.5 sin (2 t + π /4),$ where $x$ is in metre and $t$ in second. The frequency of oscillation in $Hz$ is

$2$

$π$

$π /2$

$1/ π$

Given, equation of SHM $x = - 0.5 sin (2 t + π /4)$
Now, comparing with general equation of SHM,
we get $x = A sin (ω t + ϕ)$
we get $ω = 2$ or $2 π f = 2$
or $f = \frac{1}{π} Hz$