Question

The motion of a particle executing SHM in one dimension is described by $ x=-0.5\,\sin \,(2t+\pi /4), $ where $ x $ is in metre and $t$ in second. The frequency of oscillation in $Hz$ is

• A. $ 2 $
• B. $ \pi $
• C. $ \pi /2 $
• D. $ 1/\pi $

Answer 1

Answer: (D)

Given, equation of SHM $x=-0.5 \sin (2 t+\pi / 4)$
Now, comparing with general equation of SHM,
we get $x=A \sin (\omega t+\phi)$
we get $\omega=2$ or $2 \pi f=2$
or $f=\frac{1}{\pi} H z$