The most commonly used reducing agent is

Question

The most commonly used reducing agent is (A) AlCl3  (B) PbCl2  (C) SnCl4  (D) SnCl2

Tardigrade Admin · Accepted Answer

+4 oxidation state of Sn is more stable than +2 oxidation state. Therefore, Sn 2+ can be easily oxidised to Sn 4+ and hence SnCl 2 acts a reducing agent. SnCl 2+2 Cl longrightarrow SnCl 4+2 e -

Q. The most commonly used reducing agent is

$A lC l_{3}$

$P b C l_{2}$

$S n C l_{4}$

$S n C l_{2}$

$+ 4$ oxidation state of $S n$ is more stable than $+ 2$ oxidation state.

Therefore, $S n^{2 +}$ can be easily oxidised to $S n^{4 +}$ and hence $S n C l_{2}$ acts a reducing agent.

$S n C l_{2} + 2 Cl ⟶ S n C l_{4} + 2 e^{-}$

Q. The most commonly used reducing agent is

AlCl3​

PbCl2​

SnCl4​

SnCl2​

+4 oxidation state of Sn is more stable than +2 oxidation state. Therefore, Sn2+ can be easily oxidised to Sn4+ and hence SnCl2​ acts a reducing agent. SnCl2​+2Cl⟶SnCl4​+2e−

$A lC l_{3}$

$P b C l_{2}$

$S n C l_{4}$

$S n C l_{2}$

$+ 4$ oxidation state of $S n$ is more stable than $+ 2$ oxidation state.

Therefore, $S n^{2 +}$ can be easily oxidised to $S n^{4 +}$ and hence $S n C l_{2}$ acts a reducing agent.

$S n C l_{2} + 2 Cl ⟶ S n C l_{4} + 2 e^{-}$