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  4. The most commonly used reducing agent is

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Q. The most commonly used reducing agent is

The p-Block Elements

Solution:

$+4$ oxidation state of $Sn$ is more stable than $+2$ oxidation state.

Therefore, $Sn ^{2+}$ can be easily oxidised to $Sn ^{4+}$ and hence $SnCl _{2}$ acts a reducing agent.

$SnCl _{2}+2 Cl \longrightarrow SnCl _{4}+2 e ^{-}$