The moment of inertia of a ring about its own axis is I. Then its moment of inertia, about a tangent in the plane is:

Question

The moment of inertia of a ring about its own axis is I. Then its moment of inertia, about a tangent in the plane is: (A)  (I/2)  (B)  (3I/2)  (C)  2I  (D)  (5I/2)

Tardigrade Admin · Accepted Answer

Moment of inertia of ring about its own axis I=MR2 M.I. about tangential axis I=(3/2)MR2=(3/2)I

Q. The moment of inertia of a ring about its own axis is $I .$ Then its moment of inertia, about a tangent in the plane is:

$\frac{I}{2}$

$\frac{3 I}{2}$

$2 I$

$\frac{5 I}{2}$

Moment of inertia of ring about its own axis $I = M R^{2}$ M.I. about tangential axis $I = \frac{3}{2} M R^{2} = \frac{3}{2} I$

Q. The moment of inertia of a ring about its own axis is I. Then its moment of inertia, about a tangent in the plane is:

2I​

23I​

2I

25I​