Tardigrade
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Physics
The moment of inertia of a ring about its own axis is I. Then its moment of inertia, about a tangent in the plane is:
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Q. The moment of inertia of a ring about its own axis is $ I. $ Then its moment of inertia, about a tangent in the plane is:
Rajasthan PMT
Rajasthan PMT 1995
A
$ \frac{I}{2} $
B
$ \frac{3I}{2} $
C
$ 2I $
D
$ \frac{5I}{2} $
Solution:
Moment of inertia of ring about its own axis $ I=M{{R}^{2}} $ M.I. about tangential axis $ I=\frac{3}{2}M{{R}^{2}}=\frac{3}{2}I $