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Q. The moment of inertia of a ring about its own axis is $ I. $ Then its moment of inertia, about a tangent in the plane is:

Rajasthan PMTRajasthan PMT 1995

Solution:

Moment of inertia of ring about its own axis $ I=M{{R}^{2}} $ M.I. about tangential axis $ I=\frac{3}{2}M{{R}^{2}}=\frac{3}{2}I $