Question

The molecules present in $5.6L$ of sulphur dioxide at STP is

• A. $1.5\times 10^{23}$
• B. $1.5\times 10^{-23}$
• C. $4\times 10^{23}$
• D. $0.15\times 10^{23}$

Answer 1

Answer: (A)

Number of moles in $5.6LS{O}_2=\frac{5.6}{22.4}=0.25$
$\therefore$ Number of molecules in $5.6LS{O}_2$
$=0.25\times 6.023\times 10^{23}$
$=1.50\times 10^{23}$