Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The molecules present in $5.6\, L$ of sulphur dioxide at STP is

J & K CETJ & K CET 2010Some Basic Concepts of Chemistry

Solution:

Number of moles in $5.6 L SO _{2}=\frac{5.6}{22.4}=0.25$
$\therefore $ Number of molecules in $5.6\, L\, SO _{2}$
$=0.25 \times 6.023 \times 10^{23}$
$=1.50 \times 10^{23}$