Question

The molarity of $C{l}^{-}$ in an aqueous solution which was $(w/V)2$, $4$ and $6$ will be

• A. $0.342$
• B. $0.721$
• C. $1.12$
• D. $2.18$

Answer 1

Answer: (D)

Moles of $C{l}^1$ in $100ml$ of solution
$=\frac{2}{58.5}+\frac{4}{111}\times 2+\frac{6}{53.5}=0.2184$
Molarity of $C{l}^{-}=\frac{0.2184}{100}\times 1000=2.184$