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  4. The molarity of Cl- in an aqueous solution which was (w/V) 2% NaCI, 4% CaCl2 and 6% NH4Cl will be

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Q. The molarity of $Cl^-$ in an aqueous solution which was $(w/V) \,2% \,NaCI$, $4% \,CaCl_2$ and $6% \,NH_4Cl$ will be

Some Basic Concepts of Chemistry

Solution:

Moles of $Cl^1$ in $100 \,ml$ of solution
$= \frac{2}{58.5} + \frac{4 }{111} \times 2 + \frac{6}{53.5} = 0.2184$
Molarity of $Cl^{-} = \frac{0.2184}{100} \times 1000 = 2.184$