The molarity of a solution having 18 g of glucose (mol w.t. = 180) dissolved in 500 g of water is:

Question

The molarity of a solution having 18 g of glucose (mol w.t. = 180) dissolved in 500 g of water is: (A) 2.2 M (B) 0.2 M (C) 0.5 M (D) 0.1 M

Tardigrade Admin · Accepted Answer

Molarity of glucose solution =( textweight textof textglucose/ textmolecular textweight textof textglucose)× volume (in litre) =(18/180× (500)1000)=0.2 M

Q. The molarity of a solution having 18 g of glucose (mol w.t. = 180) dissolved in 500 g of water is:

2.2 M

0.2 M

0.5 M

0.1 M

Molarity of glucose solution $= \frac{weight of glucose}{molecular weight of glucose} \times v o l u m e (in l i t re)$ $= \frac{18}{180 \times \frac{500}{1000}} = 0.2 M$

Q. The molarity of a solution having 18 g of glucose (mol w.t. = 180) dissolved in 500 g of water is:

2.2 M

0.2 M

0.5 M

0.1 M

Molarity of glucose solution =molecularweightofglucoseweightofglucose​×volume(inlitre) =180×1000500​18​=0.2M

Molarity of glucose solution $= \frac{weight of glucose}{molecular weight of glucose} \times v o l u m e (in l i t re)$ $= \frac{18}{180 \times \frac{500}{1000}} = 0.2 M$