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Q. The molarity of a solution having 18 g of glucose (mol w.t. = 180) dissolved in 500 g of water is:

JIPMERJIPMER 2001Solutions

Solution:

Molarity of glucose solution $ =\frac{\text{weight}\,\text{of}\,\text{glucose}}{\text{molecular}\,\text{weight}\,\text{of}\,\text{glucose}}\times volume\,(in\,litre) $ $ =\frac{18}{180\times \frac{500}{1000}}=0.2\,M $