Question

The molarity of 98% $H_{2}S{O}_4$ (d = 1.8 g/mL) by weight is

• A. 6 M
• B. 18 M
• C. 10 M
• D. 4 M

Answer 1

Answer: (B)

$98\%d=1.8g/ml=x$
Molar mass of $H_{2}S{O}_4=98g$
Molarity $=\frac{10\times x\times d}{\text{ Molar mass }}=\frac{10\times 98\times 1.8}{98}=10\times 1.8$
Molarity $=18M=18mol{L}^{-1}$