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  4. The molarity of 98% H2SO4 (d = 1.8 g/mL) by weight is

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Q. The molarity of 98% $H_2SO_4$ (d = 1.8 g/mL) by weight is

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Solution:

$98 \% d =1.8 g / ml = x$
Molar mass of $H _{2} SO _{4}=98 g$
Molarity $=\frac{10 \times x \times d }{\text { Molar mass }}=\frac{10 \times 98 \times 1.8}{98}=10 \times 1.8$
Molarity $=18 M =18 molL ^{-1}$