The molarity of 98% H2SO4 (d= 1.8 g/mL) by weight, is

Question

The molarity of 98% H2SO4 (d= 1.8 g/mL) by weight, is (A)  6M  (B)  18M  (C)  10M  (D)  4M

Tardigrade Admin · Accepted Answer

98% H2SO4 means 98 g H2SO4 in 100 g solution i.e., volume of the solution =(100/1.8)mL=55.55mL 98 text g text H2 textS textO4=1 text mol ∴ Molarity=(moles of the solute/volume of solution (in mL)) × 1000 =(1/55.55)× 1000=18M

Q. The molarity of 98% $H_{2} S O_{4}$ (d= 1.8 g/mL) by weight, is

$6 M$

$18 M$

$10 M$

$4 M$

Q. The molarity of 98% H2​SO4​ (d= 1.8 g/mL) by weight, is

6M

18M

10M

4M

98% H2​SO4​ means 98 g H2​SO4​ in 100 g solution i.e., volume of the solution =1.8100​mL=55.55mL 98gH2​SO4​=1mol ∴ Molarity=volumeofsolution(inmL)molesofthesolute​ ×1000 =55.551​×1000=18M

Q. The molarity of 98% $H_{2} S O_{4}$ (d= 1.8 g/mL) by weight, is

$6 M$

$18 M$

$10 M$

$4 M$