1. Tardigrade
  2. Question
  3. Chemistry
  4. The molarity of 98% H2SO4 (d= 1.8 g/mL) by weight, is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The molarity of 98% $ {{H}_{2}}S{{O}_{4}} $ (d= 1.8 g/mL) by weight, is

BVP MedicalBVP Medical 2012

Solution:

98% $ {{H}_{2}}S{{O}_{4}} $ means 98 g $ {{H}_{2}}S{{O}_{4}} $ in 100 g solution i.e., volume of the solution $ =\frac{100}{1.8}mL=55.55mL $ $ 98\text{ }g\text{ }{{H}_{2}}\text{S}{{\text{O}}_{4}}=1\text{ }mol $ $ \therefore $ $ Molarity=\frac{moles\,of\,the\,solute}{volume\,of\,solution\,(in\,mL)} $ $ \times 1000 $ $ =\frac{1}{55.55}\times 1000=18M $