Question

The molarity of $30$ mass $\%H_{2}S{O}_4$ solution of density $1.14gc{m}^{-3}$ is ______.

Answer 1

Answer: 3.49

Volume of $100g$ solution, $V=\frac{m}{d}$

$=\frac{100g}{1.14gc{m}^{-3}}=87.72c{m}^3$

Amount of sulphuric acid in $100g$ solution $=30g$

$\therefore$ No. of moles of sulphuric acid $(n)=\frac{m}{M}=\frac{30.0g}{98gmo{l}^{-1}}$

$=0.306$

Molarity of sulphuric acid,

$M=\frac{n}{V}=\frac{0.306mol}{87.72\times 10^{-3}L}$

$=3.49mo{l}^{-1}L$