The molar conductivities ∧N a O ∧ c° and ∧H C l° at infinite dilution in water at 25° C are 91.0 and 426.2 S cm 2 / mol respectively. To calculate ∧H O A c°, additional value required is:

Question

The molar conductivities ∧N a O ∧ c° and ∧H C l° at infinite dilution in water at 25° C are 91.0 and 426.2 S cm 2 / mol respectively. To calculate ∧H O A c°, additional value required is: (A) ∧°H2 O (B) ∧°KCl (C) ∧°NaoH (D) ∧°NaCl

Tardigrade Admin · Accepted Answer

According to Kohlrausch's law- thus on adding (II) and (III) if λN a+° and λC l-° are subtracted we can obtained the value of λH O A C° . Thus, additional value required is λN a C l°.

Q. The molar conductivities $\land_{N a O \land c}^{\circ}$ and $\land_{H Cl}^{\circ}$ at infinite dilution in water at $2 5^{\circ} C$ are $91.0$ and $426.2 S c m^{2} /$ mol respectively. To calculate $\land_{H O A c}^{\circ}$ , additional value required is:

$\land_{H_{2} O}^{\circ}$

$\land_{K Cl}^{\circ}$

$\land_{N a oH}^{\circ}$

$\land_{N a Cl}^{\circ}$

According to Kohlrausch's law- thus on adding (II) and (III) if $λ_{N a^{+}}^{\circ}$ and $λ_{C l^{-}}^{\circ}$ are subtracted we can obtained the value of $λ_{H O A C}^{\circ} .$ Thus, additional value required is $λ_{N a Cl}^{\circ}$ .

Q. The molar conductivities ∧NaO∧c∘​ and ∧HCl∘​ at infinite dilution in water at 25∘C are 91.0 and 426.2Scm2/ mol respectively. To calculate ∧HOAc∘​, additional value required is:

∧H2​O∘​

∧KCl∘​

∧NaoH∘​

∧NaCl∘​