Q. The molar conductivities $\wedge_{N a O \wedge c}^{\circ}$ and $\wedge_{H C l}^{\circ}$ at infinite dilution in water at $25^{\circ} C$ are $91.0$ and $426.2 \,S\, cm ^{2} /$ mol respectively. To calculate $\wedge_{H O A c}^{\circ}$, additional value required is:
AIEEEAIEEE 2006Electrochemistry
Solution:
According to Kohlrausch's law- thus on adding (II) and (III) if $\lambda_{N a^{+}}^{\circ}$ and $\lambda_{C l^{-}}^{\circ}$ are subtracted we can obtained the value of $\lambda_{H O A C}^{\circ} .$ Thus, additional value required is $\lambda_{N a C l}^{\circ}$.
