The molar concentration of chloride ion in a solution made by adding 300 ml of 3.0 M KCl solution to a 200 ml of 4.0 M BaCl 2 solution will be :-

Question

The molar concentration of chloride ion in a solution made by adding 300 ml of 3.0 M KCl solution to a 200 ml of 4.0 M BaCl 2 solution will be :- (A) 5.0 M (B) 1.8 M (C) 1.6 M (D) None of these

Tardigrade Admin · Accepted Answer

300 ×+200 × 8=x × 500 900+1600=x × 500 x=(2500/500) =5 M

Q. The molar concentration of chloride ion in a solution made by adding $300 m l$ of $3.0 M K Cl$ solution to a $200 m l$ of $4.0 M B a C l_{2}$ solution will be :-

5.0 M

1.8 M

1.6 M

None of these

$300 \times + 200 \times 8 = x \times 500$
$900 + 1600 = x \times 500$
$x = \frac{2500}{500}$
$= 5 M$

Q. The molar concentration of chloride ion in a solution made by adding 300ml of 3.0MKCl solution to a 200ml of 4.0MBaCl2​ solution will be :-