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Q. The molar concentration of chloride ion in a solution made by adding $300\, ml$ of $3.0\, M\, KCl$ solution to a $200\, ml$ of $4.0\, M\, BaCl _{2}$ solution will be :-

Solution:

$300 \times+200 \times 8=x \times 500$
$900+1600=x \times 500$
$x=\frac{2500}{500} $
$=5\, M$