The molality of 90% H2SO4 solution is [density =1.8 text g text ml ]:

Question

The molality of 90% H2SO4 solution is [density =1.8 text g text ml ]: (A) 1.8 (B) 48.4 (C) 91.8 (D) 94.6

Tardigrade Admin · Accepted Answer

The density of solution =1.8 text g text ml Weight of one litre of solution = 1800 g ∴ weight of H2SO4 in the solution =(1800× 90/100) =1620g ∴ weight of solvent =1800-1620 =180gm ∴ molality =(1620/98)× (100/180)=91.8

Q. The molality of 90% $H_{2} S O_{4}$ solution is [density $= 1.8 g m l$ ]:

1.8

48.4

91.8

94.6

The density of solution $= 1.8 g m l$ Weight of one litre of solution = 1800 g $∴$ weight of $H_{2} S O_{4}$ in the solution $= \frac{1800 \times 90}{100}$ $= 1620 g$ $∴$ weight of solvent $= 1800 - 1620$ $= 180 g m$ $∴$ molality $= \frac{1620}{98} \times \frac{100}{180} = 91.8$

Q. The molality of 90% H2​SO4​ solution is [density =1.8gml ]:

1.8

48.4

91.8

94.6

The density of solution =1.8gml Weight of one litre of solution = 1800 g ∴ weight of H2​SO4​ in the solution =1001800×90​ =1620g ∴ weight of solvent =1800−1620 =180gm ∴ molality =981620​×180100​=91.8

Q. The molality of 90% $H_{2} S O_{4}$ solution is [density $= 1.8 g m l$ ]:

The density of solution $= 1.8 g m l$ Weight of one litre of solution = 1800 g $∴$ weight of $H_{2} S O_{4}$ in the solution $= \frac{1800 \times 90}{100}$ $= 1620 g$ $∴$ weight of solvent $= 1800 - 1620$ $= 180 g m$ $∴$ molality $= \frac{1620}{98} \times \frac{100}{180} = 91.8$