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Q. The molality of 90% $ {{H}_{2}}S{{O}_{4}} $ solution is [density $ =1.8\text{ }g\text{ }ml $ ]:

ManipalManipal 2000

Solution:

The density of solution $ =1.8\text{ }g\text{ }ml $ Weight of one litre of solution = 1800 g $ \therefore $ weight of $ {{H}_{2}}S{{O}_{4}} $ in the solution $ =\frac{1800\times 90}{100} $ $ =1620g $ $ \therefore $ weight of solvent $ =1800-1620 $ $ =180gm $ $ \therefore $ molality $ =\frac{1620}{98}\times \frac{100}{180}=91.8 $