The molality of 648 g of pure water is

Question

The molality of 648 g of pure water is (A) 36 m (B) 55.5 m (C) 3.6 m (D) 5.55 m

Tardigrade Admin · Accepted Answer

Molality =( text no of moles of solute / text mass of solvent in kg ) Molar mass of water =18 g Mass of water =648 g No of moles of water =(648/18)=36 mol Molality =(36 × 1000/648)=55.5 m

Q. The molality of $648 g$ of pure water is

$36 m$

$55.5 m$

$3.6 m$

$5.55 m$

Molality $= \frac{no of moles of solute}{mass of solvent in kg}$
Molar mass of water $= 18 g$
Mass of water $= 648 g$
No of moles of water $= \frac{648}{18} = 36 m o l$
Molality $= \frac{36 \times 1000}{648} = 55.5 m$

Q. The molality of 648g of pure water is

36m

55.5m

3.6m

5.55m